inputs/lecture_09.tex

@@ -40,7 +40,6 @@ We will see that  not every analytic set is Borel.
     $f$ is continuous
     by the weaker assertion of $f$ being Borel.
     \todo{Copy exercise from sheet 5}
-    % TODO WHY?
 \end{remark}
 
 \begin{theorem}

inputs/lecture_10.tex

@@ -1,6 +1,5 @@
-\subsection{The Lusin Separation Theorem}
-
 \lecture{10}{2023-11-17}{}
+\todo{Start a new subsection here?}
 \begin{theorem}[\vocab{Lusin separation theorem}]
     \yalabel{Lusin Separation Theorem}{Lusin Separation}{thm:lusinseparation}
     Let $X$ be Polish and $A,B \subseteq  X$ disjoint analytic.
@@ -56,7 +55,7 @@ we need the following definition:
     such that $A \cap B = \emptyset$
     Then there are continuous surjections
     $f\colon \cN \twoheadrightarrow  A \subseteq X$
-    and $g\colon \cN \twoheadrightarrow B \subseteq X$.
+    and $g\colon \twoheadrightarrow B \subseteq X$.
 
     Write $A_s \coloneqq  f(\cN_s)$ and $B_s \coloneqq g(\cN_s)$.
     Note that $A_s = \bigcup_m A_{s\concat m}$
@@ -106,8 +105,8 @@ we need the following definition:
     Then  $f(A)$ is Borel.
 \end{theorem}
 \begin{refproof}{thm:lusinsouslin}
-    W.l.o.g.~suppose that $f$ is continuous,
-    $A$ is closed\footnote{We might even assume that $A$ is clopen, but we only need closed.}
+    W.l.o.g.~suppose that $f$ is continuous
+    $A$ is closed,\footnote{We might even assume that $A$ is clopen, but we only need closed.}
     and $X = \cN$ by \yaref{thm:bairetopolish}:
 
 
@@ -140,7 +139,7 @@ we need the following definition:
     \end{itemize}
     The second point follows from injectivity of $f$
     and the fact that $\cN_{s \concat n} \cap \cN_{s\concat n'} = \emptyset$.
-    In particular, the $(B_s)$ form a Lusin scheme.
+    In particular, the $(B_s)$ for a Lusin scheme.
 
     Note that $f(A) = \bigcup_{s \in \omega^k} B_s$
     for every $k <\omega$,

inputs/lecture_11.tex

@@ -118,7 +118,7 @@
     Hence \yaref{thm:bsb} can be applied.
 \end{proof}
 
-\subsection{The Projective Hierarchy}
+\subsection{Projective Hierarchy}
 
         
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@@ -151,7 +151,7 @@
 We will not proof this in this lecture.
 
 
-\subsection{Ill-Founded Trees}
+\subsection{Trees} % TODO section?
 
 
 Recall that a \vocab{tree} on $\N$ is a subset of