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inputs/lecture_11.tex

@@ -110,11 +110,11 @@
     Whenever $B \subseteq  X$ is Borel,
     we have that $b^{-1}(B)$ is Borel,
     since $b$ is continuous.
-    For $A \subseteq \cN$ is Borel,
-    we have that $b$ with respect to $b(A)$
+    For $A \subseteq D$ Borel
+    be get by \yaref{thm:lusinsouslin},
+    that $b$ with respect to $b(A)$
     is Borel,
-    since $b\defon{A}$ is injective,
-    by \yaref{thm:lusinsouslin}.
+    since $b\defon{A}$ is injective.
 
     Hence \yaref{thm:bsb} can be applied.
 \end{proof}