From de2d240c5a46fefc16b6ce89fd6849e373be5646 Mon Sep 17 00:00:00 2001 From: Josia Pietsch Date: Tue, 6 Feb 2024 15:16:20 +0100 Subject: [PATCH] more details --- inputs/lecture_11.tex | 8 ++++---- 1 file changed, 4 insertions(+), 4 deletions(-) diff --git a/inputs/lecture_11.tex b/inputs/lecture_11.tex index 5174717..e4193dc 100644 --- a/inputs/lecture_11.tex +++ b/inputs/lecture_11.tex @@ -110,11 +110,11 @@ Whenever $B \subseteq X$ is Borel, we have that $b^{-1}(B)$ is Borel, since $b$ is continuous. - For $A \subseteq \cN$ is Borel, - we have that $b$ with respect to $b(A)$ + For $A \subseteq D$ Borel + be get by \yaref{thm:lusinsouslin}, + that $b$ with respect to $b(A)$ is Borel, - since $b\defon{A}$ is injective, - by \yaref{thm:lusinsouslin}. + since $b\defon{A}$ is injective. Hence \yaref{thm:bsb} can be applied. \end{proof}