remark on stationary sets, closedness of diagonal intersection
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@ -150,11 +150,20 @@ We have shown (assuming \AxC to choose contained clubs):
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The \vocab{diagonal intersection},
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The \vocab{diagonal intersection},
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is defined to be
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is defined to be
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\[
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\[
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\diagi_{\beta < \alpha} A_{\beta} \coloneqq
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\diagi_{\beta < \alpha} A_{\beta} \coloneqq
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\{\xi < \alpha : \xi \in \bigcap \{A_{\beta} : \beta < \xi\} \}
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\{\xi < \alpha : \xi \in \bigcap \{A_{\beta} : \beta < \xi\} \}
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= \bigcap_{\beta < \alpha} ([0,\beta] \cup A_\beta)
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= \bigcap_{\beta < \alpha} ([0,\beta] \cup A_\beta)
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\]
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\]
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\end{definition}
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\end{definition}
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\begin{remark}+
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\label{rem:diagiclosed}
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Note that if $A$ is closed,
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so is $[0,\alpha] \cup A$.
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Since the intersection of arbitrarily many
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closed sets is closed,
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we get that the diagonal intersection
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of closed sets is closed.
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\end{remark}
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\begin{lemma}
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\begin{lemma}
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\label{lem:diagiclub}
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\label{lem:diagiclub}
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Let $\kappa$ be a regular, uncountable cardinal.
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Let $\kappa$ be a regular, uncountable cardinal.
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@ -181,22 +190,23 @@ We have shown (assuming \AxC to choose contained clubs):
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$\diagi_{\beta < \kappa} D_{\beta}$ is closed in $\kappa$.
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$\diagi_{\beta < \kappa} D_{\beta}$ is closed in $\kappa$.
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\end{claim}
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\end{claim}
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\begin{subproof}
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\begin{subproof}
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Let $\gamma < \kappa$ be such that $\left( \diagi_{\beta < \kappa} D_{\beta} \right) \cap \gamma$
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Cf.~\yaref{rem:diagiclosed}.
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is unbounded in $\gamma$.
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% Let $\gamma < \kappa$ be such that $\left( \diagi_{\beta < \kappa} D_{\beta} \right) \cap \gamma$
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We aim to show that $\gamma \in \diagi_{\beta < \kappa} D_{\beta}$.
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% is unbounded in $\gamma$.
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Let $\beta_0 < \gamma$.
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% We aim to show that $\gamma \in \diagi_{\beta < \kappa} D_{\beta}$.
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We need to see that $\gamma \in D_{\beta_0}$.
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% Let $\beta_0 < \gamma$.
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% We need to see that $\gamma \in D_{\beta_0}$.
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For each $\beta_0 \le \beta' < \gamma$
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% For each $\beta_0 \le \beta' < \gamma$
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there is some $\beta'' \in \diagi_{\beta < \kappa} D_\beta$
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% there is some $\beta'' \in \diagi_{\beta < \kappa} D_\beta$
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such that $\beta' \le \beta'' < \gamma$,
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% such that $\beta' \le \beta'' < \gamma$,
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since $\gamma = \sup((\diagi_{\beta < \kappa} D_\beta) \cap \gamma)$.
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% since $\gamma = \sup((\diagi_{\beta < \kappa} D_\beta) \cap \gamma)$.
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In particular $\beta'' \in D_{\beta_0}$.
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% In particular $\beta'' \in D_{\beta_0}$.
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So $D_{\beta_0} \cap \gamma$
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% So $D_{\beta_0} \cap \gamma$
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is unbounded in $\gamma$.
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% is unbounded in $\gamma$.
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Since $D_{\beta_0}$ is closed
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% Since $D_{\beta_0}$ is closed
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it follows that $\gamma \in D_{\beta_0}$.
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% it follows that $\gamma \in D_{\beta_0}$.
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%As $\beta_0 < \gamma$ was arbitrary,
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%As $\beta_0 < \gamma$ was arbitrary,
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%this shows that $\gamma \in \diagi_{\beta < n} D_\beta$.
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%this shows that $\gamma \in \diagi_{\beta < n} D_\beta$.
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@ -288,6 +298,20 @@ We have shown (assuming \AxC to choose contained clubs):
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iff $C \cap S \neq \emptyset$
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iff $C \cap S \neq \emptyset$
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for every club $C \subseteq \kappa$.
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for every club $C \subseteq \kappa$.
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\end{definition}
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\end{definition}
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\begin{remark}+[\url{https://mathoverflow.net/q/37503}]
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Informally, club sets and stationary sets
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can be viewed as large sets of a measure space
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of measure $1$.
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Clubs behave similarly to sets of measure $1$
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and stationary sets are analogous to
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sets of positive measure:
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\begin{itemize}
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\item Every club is stationary,
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\item the intersection of two clubs is a club,
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\item the intersection of a club and a stationary set is stationary,
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\item there exist disjoint stationary sets.
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\end{itemize}
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\end{remark}
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\begin{example}
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\begin{example}
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\begin{itemize}
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\begin{itemize}
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\item Every $D \subseteq \kappa$ which is club in $\kappa$
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\item Every $D \subseteq \kappa$ which is club in $\kappa$
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