remark on stationary sets, closedness of diagonal intersection

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Josia Pietsch 2024-02-16 19:28:21 +01:00
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@ -155,6 +155,15 @@ We have shown (assuming \AxC to choose contained clubs):
= \bigcap_{\beta < \alpha} ([0,\beta] \cup A_\beta) = \bigcap_{\beta < \alpha} ([0,\beta] \cup A_\beta)
\] \]
\end{definition} \end{definition}
\begin{remark}+
\label{rem:diagiclosed}
Note that if $A$ is closed,
so is $[0,\alpha] \cup A$.
Since the intersection of arbitrarily many
closed sets is closed,
we get that the diagonal intersection
of closed sets is closed.
\end{remark}
\begin{lemma} \begin{lemma}
\label{lem:diagiclub} \label{lem:diagiclub}
Let $\kappa$ be a regular, uncountable cardinal. Let $\kappa$ be a regular, uncountable cardinal.
@ -181,22 +190,23 @@ We have shown (assuming \AxC to choose contained clubs):
$\diagi_{\beta < \kappa} D_{\beta}$ is closed in $\kappa$. $\diagi_{\beta < \kappa} D_{\beta}$ is closed in $\kappa$.
\end{claim} \end{claim}
\begin{subproof} \begin{subproof}
Let $\gamma < \kappa$ be such that $\left( \diagi_{\beta < \kappa} D_{\beta} \right) \cap \gamma$ Cf.~\yaref{rem:diagiclosed}.
is unbounded in $\gamma$. % Let $\gamma < \kappa$ be such that $\left( \diagi_{\beta < \kappa} D_{\beta} \right) \cap \gamma$
We aim to show that $\gamma \in \diagi_{\beta < \kappa} D_{\beta}$. % is unbounded in $\gamma$.
Let $\beta_0 < \gamma$. % We aim to show that $\gamma \in \diagi_{\beta < \kappa} D_{\beta}$.
We need to see that $\gamma \in D_{\beta_0}$. % Let $\beta_0 < \gamma$.
% We need to see that $\gamma \in D_{\beta_0}$.
For each $\beta_0 \le \beta' < \gamma$ % For each $\beta_0 \le \beta' < \gamma$
there is some $\beta'' \in \diagi_{\beta < \kappa} D_\beta$ % there is some $\beta'' \in \diagi_{\beta < \kappa} D_\beta$
such that $\beta' \le \beta'' < \gamma$, % such that $\beta' \le \beta'' < \gamma$,
since $\gamma = \sup((\diagi_{\beta < \kappa} D_\beta) \cap \gamma)$. % since $\gamma = \sup((\diagi_{\beta < \kappa} D_\beta) \cap \gamma)$.
In particular $\beta'' \in D_{\beta_0}$. % In particular $\beta'' \in D_{\beta_0}$.
So $D_{\beta_0} \cap \gamma$ % So $D_{\beta_0} \cap \gamma$
is unbounded in $\gamma$. % is unbounded in $\gamma$.
Since $D_{\beta_0}$ is closed % Since $D_{\beta_0}$ is closed
it follows that $\gamma \in D_{\beta_0}$. % it follows that $\gamma \in D_{\beta_0}$.
%As $\beta_0 < \gamma$ was arbitrary, %As $\beta_0 < \gamma$ was arbitrary,
%this shows that $\gamma \in \diagi_{\beta < n} D_\beta$. %this shows that $\gamma \in \diagi_{\beta < n} D_\beta$.
@ -288,6 +298,20 @@ We have shown (assuming \AxC to choose contained clubs):
iff $C \cap S \neq \emptyset$ iff $C \cap S \neq \emptyset$
for every club $C \subseteq \kappa$. for every club $C \subseteq \kappa$.
\end{definition} \end{definition}
\begin{remark}+[\url{https://mathoverflow.net/q/37503}]
Informally, club sets and stationary sets
can be viewed as large sets of a measure space
of measure $1$.
Clubs behave similarly to sets of measure $1$
and stationary sets are analogous to
sets of positive measure:
\begin{itemize}
\item Every club is stationary,
\item the intersection of two clubs is a club,
\item the intersection of a club and a stationary set is stationary,
\item there exist disjoint stationary sets.
\end{itemize}
\end{remark}
\begin{example} \begin{example}
\begin{itemize} \begin{itemize}
\item Every $D \subseteq \kappa$ which is club in $\kappa$ \item Every $D \subseteq \kappa$ which is club in $\kappa$