175 lines
No EOL
4.7 KiB
C++
175 lines
No EOL
4.7 KiB
C++
// Algorithm deciding if two rooted trees are isomorphic
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// Authors: Georǵi Kocharyan
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#include <iostream>
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#include <cstdio>
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#include <vector>
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#include <list>
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#include <queue>
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#include <algorithm>
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#include <string>
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// Node has to store parent to make naming possible in linear time
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struct TreeNode {
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std::vector<TreeNode*> children;
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std::string name;
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TreeNode* parent;
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TreeNode() = default;
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TreeNode(TreeNode* node) : parent(node) {}
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void add_child()
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{
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children.push_back(new TreeNode(this));
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}
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};
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// outputs a vector of lists of each depth of the tree
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std::vector<std::list<TreeNode*>> tree_levels(TreeNode* root) {
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if (!root) return {};
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std::vector<std::list<TreeNode*>> result;
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std::queue<std::pair<TreeNode*, int>> q;
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q.push(std::make_pair(root, 0));
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while (!q.empty())
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{
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TreeNode* node = q.front().first;
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int depth = q.front().second;
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q.pop();
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// If this is a new depth, add a new list to the result
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if (depth >= result.size()) {
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result.push_back(std::list<TreeNode*>());
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}
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// Add the current node's value to the appropriate depth list
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result[depth].push_back(node);
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// Enqueue children with their depth
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for (const auto& child : node->children) {
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q.push(std::make_pair(child, depth + 1));
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}
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}
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return result;
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}
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bool lexicographicOrder(TreeNode* a,TreeNode* b) {
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return (a->name)<(b->name);
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}
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// to do: actually implement linear bucket sort
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void bucketSort(std::list<TreeNode*>& nodes) {
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if (nodes.empty()) return;
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nodes.sort(lexicographicOrder);
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}
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int main() {
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// initialise tree 1
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TreeNode* root = new TreeNode();
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root->add_child();
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root->add_child();
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root->add_child();
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root->children[1]->add_child();
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root->children[1]->add_child();
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root->children[2]->add_child();
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root->children[1]->children[1]->add_child();
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root->children[2]->children[0]->add_child();
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root->children[2]->children[0]->add_child();
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// initialise tree 2
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TreeNode* root2 = new TreeNode();
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root2->add_child();
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root2->add_child();
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root2->add_child();
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root2->children[0]->add_child();
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root2->children[2]->add_child();
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root2->children[2]->add_child();
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root2->children[0]->children[0]->add_child();
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root2->children[2]->children[1]->add_child();
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root2->children[2]->children[1]->add_child();
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// store all nodes by their depth
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std::vector<std::list<TreeNode*>> levels1 = tree_levels(root);
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std::vector<std::list<TreeNode*>> levels2 = tree_levels(root2);
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int height = levels1.size()-1;
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// if heights are different trees cannot be isomorphic
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if (!(height == levels2.size()-1))
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{
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std::cout << "Trees are not isomorphic. Their heights are different." << std::endl;
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return 0;
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}
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// the name of all leaves is 1
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std::string s("1");
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for (auto leaf : levels1[height])
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{
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leaf->name = s;
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}
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for (auto leaf : levels2[height])
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{
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leaf->name = s;
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}
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for (int i = height-1; i >= 0; i--)
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{
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int amount = levels1[i].size();
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if (!(amount == levels2[i].size()))
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{
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std::cout << "Trees are not isomorphic, they have a different number of nodes in depth " << i << "." << std::endl;
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return 0;
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}
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// name all nodes of current height by iterating through all (sorted) children
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for (const auto& node : levels1[i+1])
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{
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node->parent->name = node->parent->name + node->name;
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}
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for (const auto& node : levels2[i+1])
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{
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node->parent->name = node->parent->name + node->name;
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}
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// sort nodes of current height by name
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bucketSort(levels1[i]);
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bucketSort(levels2[i]);
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// check if both trees have the same names in the current level
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std::list<TreeNode*>::iterator itr1 = levels1[i].begin();
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std::list<TreeNode*>::iterator itr2 = levels2[i].begin();
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for (auto _ = amount; _--;)
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{
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if (!(((*itr1)->name) == ((*itr2)->name)))
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{
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std::cout << "Trees are not isomorphic!" << std::endl;
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return 0;
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}
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itr1++;
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itr2++;
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}
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// rename words according to index in sorted vector
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int count = 0;
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for (auto& node : levels1[i])
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{
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node->name = std::to_string(count);
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count++;
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}
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count = 0;
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for (auto& node : levels2[i])
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{
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node->name = std::to_string(count);
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count++;
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}
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}
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std::cout << "Trees are isomorphic." << std::endl;
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return 0;
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} |