fixed typo
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Josia Pietsch 2023-11-24 19:58:19 +01:00
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@ -143,9 +143,8 @@ For the proof we need some prerequisites:
a &: x \in A,\\ a &: x \in A,\\
b &: x \not\in A,\\ b &: x \not\in A,\\
\end{cases} \end{cases}
where $a \in \IF$ and $b \not\in \IF$
are chosen arbitrarily.
\end{IEEEeqnarray*} \end{IEEEeqnarray*}
where $a \in \IF$ and $b \not\in \IF$ are chosen arbitrarily.
\end{proof} \end{proof}
\subsection{Linear Orders} \subsection{Linear Orders}