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Josia Pietsch 2024-02-06 15:11:31 +01:00
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@ -165,7 +165,13 @@
Since the cantor space embeds into $X$,
we get the lower bound.
Since $X$ is second countable and Hausdorff,
we get the upper bound.%
we get the upper bound:
Let $\langle U_n : n < \omega \rangle$ be a countable basis.
Consider the injective function
\begin{IEEEeqnarray*}{rCl}
f\colon X &\longrightarrow & 2^{ \omega} \\
x &\longmapsto & \{n : x \in U_n\}.
\end{IEEEeqnarray*}
}{Lower bound: $2^{\N} \hookrightarrow X$,
upper bound: \nth{2} countable and Hausdorff.}
\end{proof}