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\lecture{03}{2023-1023}{Cantor-Bendixson}
\begin{theorem}[Cantor-Bendixson]
\yaref{thm:cantorbendixson}{Cantor-Bendixson}{Cantor-Bendixson}
If $A \subseteq \R$ is closed,
it is either at most countable or else
$A$ contains a perfect set.
\end{theorem}
\begin{corollary}
If $A se \R$ is closed,
then either $A \le \N$ or $A \sim \R$.
\end{corollary}
\begin{fact}
$A' = \{x \in \R | \forall a < x < b.~ (a,b) \cap A \text{ is at least countable}\}$.
\end{fact}
\begin{proof}
$\supseteq$ is clear.
For $\subseteq $, fix $a < x < b$
and let us define $(y_n: n \in \omega)$
as well as $((a_n, b_n): n \in \omega)$.
% TODO
\end{proof}