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7 changed files with 28 additions and 36 deletions
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@ -39,7 +39,6 @@
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is not a well-order on a countable set.
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is not a well-order on a countable set.
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Thus $\otp(\faktor{W}{\sim}, <) = \omega_1$.
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Thus $\otp(\faktor{W}{\sim}, <) = \omega_1$.
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\todo{move this}
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\end{remark}
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\end{remark}
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}{}
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}{}
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@ -280,9 +280,9 @@ We have shown (assuming \AxC to choose contained clubs):
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\end{refproof}
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\end{refproof}
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\begin{remark}+
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\begin{remark}+
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$\diagi_{\beta < \kappa} C_{\beta}$ actually
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$\diagi_{\beta < \kappa} C_{\beta}$ actually
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\emph{is} a club:
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\emph{is} a club,
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It suffices to show that $\diagi_{\beta < \kappa} C_\beta$ is closed.
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since $\diagi_{\beta < \kappa} C_\beta$ is closed,
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This can be shown in the same way as for $\diagi_{\beta < \kappa} D_\beta$.
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again cf.~\yaref{rem:diagiclosed}.
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% Let $\lambda < \kappa$ be a limit ordinal.
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% Let $\lambda < \kappa$ be a limit ordinal.
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% Suppose that $\lambda \not\in \diagi_{\beta < \kappa} D_\beta$.
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% Suppose that $\lambda \not\in \diagi_{\beta < \kappa} D_\beta$.
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% Then there exists $\alpha < \lambda$ such that
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% Then there exists $\alpha < \lambda$ such that
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@ -43,7 +43,6 @@ Recall that $F \subseteq \cP(\kappa)$ is a filter if
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$X,Y \in F \implies X \cap Y \in F$,
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$X,Y \in F \implies X \cap Y \in F$,
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$X \in F, X \subseteq Y \subseteq \kappa \implies Y \in F$
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$X \in F, X \subseteq Y \subseteq \kappa \implies Y \in F$
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and $\emptyset \not\in F, \kappa \in F$.
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and $\emptyset \not\in F, \kappa \in F$.
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\todo{Move this to the definition of filter?}
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}{}
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}{}
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\begin{definition}
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\begin{definition}
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A filter $F$ is an \vocab{ultrafilter}
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A filter $F$ is an \vocab{ultrafilter}
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@ -104,11 +103,7 @@ one cofinality.
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\begin{refproof}{thm:solovay}%
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\begin{refproof}{thm:solovay}%
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\gist{%
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\gist{%
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%\footnote{``This is one of the arguments where it is certainly
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\footnote{``This is one of the arguments where it is certainly worth it to look at it again.''}
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% worth it to look at it again''}
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% TODO: Look at this again and think about it.
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% TODO TODO TODO
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We will only prove this for $\aleph_1$.
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We will only prove this for $\aleph_1$.
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Fix $S \subseteq \aleph_1$ stationary.
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Fix $S \subseteq \aleph_1$ stationary.
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@ -197,19 +192,22 @@ one cofinality.
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Write $\delta_i = \delta'$ and $T_i = T$.
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Write $\delta_i = \delta'$ and $T_i = T$.
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\begin{claim}
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By construction, all the $T_i$ are stationary.
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\label{thm:solovay:p:c2}
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Since the $\delta_i$ are strictly increasing
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Each $T_i$ is stationary
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and since $\gamma_n^{\alpha} = \delta_i$ for all $\alpha \in T_i$,
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and if $i \neq j$, then $T_i \cap T_j = \emptyset$.
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we have that the $T_i$ are disjoint.
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\footnote{maybe this should not be a claim}
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% \begin{claim}
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\end{claim}
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% \label{thm:solovay:p:c2}
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\begin{subproof}
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% Each $T_i$ is stationary
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The first part is true by construction.
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% and if $i \neq j$, then $T_i \cap T_j = \emptyset$.
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Let $j < i$.
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% \end{claim}
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Then if $\alpha \in T_i$, $\alpha' \in T_j$,
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% \begin{subproof}
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we get $\gamma_n^{\alpha'} = \delta_j < \delta_i = \gamma_n^{\alpha}$
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% The first part is true by construction.
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hence $\alpha \neq \alpha'$.
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% Let $j < i$.
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\end{subproof}
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% Then if $\alpha \in T_i$, $\alpha' \in T_j$,
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% we get $\gamma_n^{\alpha'} = \delta_j < \delta_i = \gamma_n^{\alpha}$
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% hence $\alpha \neq \alpha'$.
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% \end{subproof}
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Now let
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Now let
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\[
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\[
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@ -232,8 +230,6 @@ one cofinality.
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\item $\exists n < \omega.~\forall \delta < \omega_1: \{\alpha \in S^\ast : \gamma^{\alpha}_n > \delta\}$
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\item $\exists n < \omega.~\forall \delta < \omega_1: \{\alpha \in S^\ast : \gamma^{\alpha}_n > \delta\}$
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stationary:
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stationary:
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\begin{itemize}
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\begin{itemize}
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% TODO THINK!
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% TODO TODO TODO
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\item Otherwise $\forall n < \omega.~\exists \delta.~\{\alpha \in S^\ast : \gamma^{\alpha}_n > \delta\} $ nonstationary.
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\item Otherwise $\forall n < \omega.~\exists \delta.~\{\alpha \in S^\ast : \gamma^{\alpha}_n > \delta\} $ nonstationary.
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\item $\delta_n\coloneqq $ least such $\delta$,
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\item $\delta_n\coloneqq $ least such $\delta$,
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$C_n$ club s.t.~$C_n \cap \{\alpha \in S^\ast : \gamma^{\alpha}_n > \delta_n\} = \emptyset$.
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$C_n$ club s.t.~$C_n \cap \{\alpha \in S^\ast : \gamma^{\alpha}_n > \delta_n\} = \emptyset$.
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@ -1,9 +1,6 @@
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\lecture{17}{2023-12-14}{Silver's Theorem}
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\lecture{17}{2023-12-14}{Silver's Theorem}
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We now want to prove \yaref{thm:silver}.
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We now want to prove \yaref{thm:silver}.
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% More generally, if $\kappa$ is a singular cardinal of uncountable cofinality
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% such that $2^{\lambda} = \lambda^+$ for all $\lambda < \kappa$,
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% then $2^{\kappa} = \kappa^+$.
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\gist{%
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\gist{%
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\begin{remark}
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\begin{remark}
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\end{remark}
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\end{remark}
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}{}
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}{}
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We will only proof
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We will only prove
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\gist{%
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\gist{%
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\yaref{thm:silver} in the special case that $\kappa = \aleph_{\omega_1}$
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\yaref{thm:silver} in the special case that $\kappa = \aleph_{\omega_1}$
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(see \yaref{thm:silver1}).
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(see \yaref{thm:silver1}).
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@ -153,6 +150,7 @@ We will only proof
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Let $\beta < \omega_1$ be such that for all $Y \in A_2$
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Let $\beta < \omega_1$ be such that for all $Y \in A_2$
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and for all $\alpha \in T$, $h_Y(\alpha) = \beta$.
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and for all $\alpha \in T$, $h_Y(\alpha) = \beta$.
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% TODO WHY DOES THIS WORK?
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Then $\overline{f}_Y(\alpha) < \aleph_\beta$
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Then $\overline{f}_Y(\alpha) < \aleph_\beta$
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for all $Y \in A_2$ and $\alpha \in T$.
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for all $Y \in A_2$ and $\alpha \in T$.
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@ -27,7 +27,6 @@
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Since $2^{\lambda} < \kappa$,
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Since $2^{\lambda} < \kappa$,
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\AxPow works.
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\AxPow works.
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The other axioms are trivial.
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The other axioms are trivial.
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\todo{Exercise}
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\end{proof}
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\end{proof}
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\begin{corollary}
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\begin{corollary}
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$\ZFC$ does not prove the existence of inaccessible
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$\ZFC$ does not prove the existence of inaccessible
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@ -79,6 +79,7 @@ and $\forall x \in y.~\phi$ abbreviates $\forall x.~x \in y \to \phi$.
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A similar arguments yields \vocab{upwards absoluteness} for $\Sigma_1$-formulas
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A similar arguments yields \vocab{upwards absoluteness} for $\Sigma_1$-formulas
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and \vocab{downwards absoluteness} for $\Pi_1$-formulas:
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and \vocab{downwards absoluteness} for $\Pi_1$-formulas:
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\begin{lemma}
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\begin{lemma}
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\label{lem:pi1downardsabsolute}
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Let $M$ be transitive.
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Let $M$ be transitive.
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Let $\phi(x_0,\ldots,x_n) \in \cL_\in$ and $a_0,\ldots,a_n \in M$.
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Let $\phi(x_0,\ldots,x_n) \in \cL_\in$ and $a_0,\ldots,a_n \in M$.
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Then
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Then
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@ -112,7 +112,7 @@ is well founded.
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The formula $\forall x.~\forall y .~((\forall z \in x.~z \in y \land \forall z \in y.~z \in x) \to x = y)$
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The formula $\forall x.~\forall y .~((\forall z \in x.~z \in y \land \forall z \in y.~z \in x) \to x = y)$
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is $\Pi_1$, hence it is true in $M[g]$
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is $\Pi_1$, hence it is true in $M[g]$
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by %TODO REF downward absolutenes.
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by \yaref{lem:pi1downardsabsolute}.
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\item \AxFund:
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\item \AxFund:
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Again,
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Again,
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\[
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\[
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@ -137,7 +137,7 @@ is well founded.
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so $M[g] \models \text{``$\{x,y\}$ is the pair of $x$ and $y$''}$.
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so $M[g] \models \text{``$\{x,y\}$ is the pair of $x$ and $y$''}$.
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Hence $M[g] \models \AxPair$.
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Hence $M[g] \models \AxPair$.
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\item \AxUnion:
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\item \AxUnion:
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Similar to \AxPair.\gist{\todo{Exercise}}{}
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Similar to \AxPair.
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\end{itemize}
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\end{itemize}
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\end{proof}
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\end{proof}
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\[
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\[
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p \Vdash^{\mathbb{P}}_M \phi(\tau_1,\ldots, \tau_k).
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p \Vdash^{\mathbb{P}}_M \phi(\tau_1,\ldots, \tau_k).
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\]
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\]
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\end{enumerate}
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\end{enumerate}
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\end{theorem}
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\end{theorem}
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\begin{proof}
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\begin{proof}
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