From 3d9d71fbd39fae1fa40156a0ae8294be7bf4fbde Mon Sep 17 00:00:00 2001 From: Josia Pietsch Date: Tue, 16 Jan 2024 00:06:50 +0100 Subject: [PATCH] updated proof on diagonal intersection --- inputs/lecture_14.tex | 13 +++++++------ 1 file changed, 7 insertions(+), 6 deletions(-) diff --git a/inputs/lecture_14.tex b/inputs/lecture_14.tex index e0118d9..c89af96 100644 --- a/inputs/lecture_14.tex +++ b/inputs/lecture_14.tex @@ -161,18 +161,19 @@ We have shown (assuming \AxC to choose contained clubs): is unbounded in $\gamma$. We aim to show that $\gamma \in \diagi_{\beta < \kappa} D_{\beta}$. Let $\beta_0 < \gamma$. - We need to see $\gamma \in D_{\beta_0}$. - For each $\beta'$ with $\beta < \beta' < \gamma$, + We need to see that $\gamma \in D_{\beta_0}$. + For each $\beta_0 \le \beta' < \gamma$ there is some $\beta'' \in \diagi_{\beta < \kappa} D_\beta$ - with $\beta'' \ge \beta', \beta'' < \gamma$. + such that $\beta' \le \beta'' < \gamma$, + since $\gamma = \sup((\diagi_{\beta < \kappa} D_\beta) \cap \gamma)$. In particular $\beta'' \in D_{\beta_0}$. We showed that $D_{\beta_0} \cap \gamma$ is unbounded in $\gamma$, - so $\gamma \in D_{\beta_0}$. + so $\gamma \in D_{\beta_0}$, since $D_{\beta_0}$ is closed. - As $\beta_0 < \gamma$ was arbitrary, - this shows that $\gamma \in \diagi_{\beta < n} D_\beta$. + %As $\beta_0 < \gamma$ was arbitrary, + %this shows that $\gamma \in \diagi_{\beta < n} D_\beta$. \end{subproof} \begin{claim}