fixed chebyshev

This commit is contained in:
Josia Pietsch 2023-07-17 12:36:38 +02:00
parent 3e816f515e
commit 28bc88cbc5
Signed by untrusted user who does not match committer: josia
GPG Key ID: E70B571D66986A2D
2 changed files with 3 additions and 2 deletions

View File

@ -197,6 +197,7 @@ Typically $\cF_n = \sigma(X_1, \ldots, X_n)$ for a sequence of random variables.
\footnote{In this form it means, that there is some filtration,
that we don't explicitly specify}.
Then $(f(X_n))_n$ is a sub-martingale.
Likewise, if $f$ is concave, then $((f(X_n))_n$ is a super-martingale.
\end{corollary}
\begin{proof}
Apply \autoref{cjensen}.

View File

@ -280,7 +280,7 @@ This is taken from section 6.1 of the notes on Stochastik.
Let $X$ be a random variable and $a > 0$.
Then
\[
\bP[|X - \bE(X)| \ge a] \le \frac{\Var(X)}{a}.
\bP[|X - \bE(X)| \ge a] \le \frac{\Var(X)}{a^2}.
\]
\end{theorem}
\begin{proof}
@ -288,7 +288,7 @@ This is taken from section 6.1 of the notes on Stochastik.
\begin{IEEEeqnarray*}{rCl}
\bP[|X-\bE(X)| \ge a]
&=& \bP[|X - \bE(X)|^2 \ge a^2]\\
&\overset{\text{Markov}}{\ge}& \frac{\bE[|X - \bE(X)|^2]}{a^2}.
&\overset{\text{Markov}}{\le}& \frac{\bE[|X - \bE(X)|^2]}{a^2}.
\end{IEEEeqnarray*}
\end{proof}