From 2204004e6397ae96967d98150bcf07101d646870 Mon Sep 17 00:00:00 2001
From: =?UTF-8?q?Maximilian=20Ke=C3=9Fler?= <git@maximilian-kessler.de>
Date: Wed, 16 Feb 2022 01:32:03 +0100
Subject: [PATCH] fix tizkcd figure

---
 2021_Algebra_I.tex | 6 ++----
 1 file changed, 2 insertions(+), 4 deletions(-)

diff --git a/2021_Algebra_I.tex b/2021_Algebra_I.tex
index dc0d785..f53507e 100644
--- a/2021_Algebra_I.tex
+++ b/2021_Algebra_I.tex
@@ -851,14 +851,12 @@ The following will lead to another proof of the Nullstellensatz, which uses the
     \label{artintate}
     Let $A$ be a subalgebra of the $R$-algebra $B$, where $R$ is Noetherian. If $ B / R$ is of finite type and $B / A$ is finite, then $A / R$ is also of finite type.
 
-    \begin{figure}[H]
-        \centering
+      \[
         \begin{tikzcd}
             A \arrow[hookrightarrow]{rr}{\subseteq}& & B  \\
                             &R \arrow{ul}{\alpha} \arrow{ur}{\alpha} \text{~(Noeth.)}
         \end{tikzcd}
-    \end{figure}
-    
+      \]
 \end{proposition}
 \begin{proof}
     Let $(b_i)_{i=1}^{m}$ generate $B$ as an $A$-module and $(\beta_j)_{j=1}^m$ as an $R$-algebra.